Refer to the exhibit. Which statement explains the configuration error message that is received?
Refer to the exhibit. Which statement explains the configuration error message that is received?
The configuration error message appears because the IP address 192.168.16.143 with a subnet mask of 255.255.255.240 (/28) is a broadcast address. In a /28 network, each subnet has 16 IP addresses. The subnet that includes 192.168.16.143 has an IP range from 192.168.16.128 to 192.168.16.143, where 192.168.16.143 is the broadcast address and cannot be assigned to a device.
For /28 network, There (2^4)=16 Subnets with each having (2^4-2)=14 host (14 +1 Network ID+ 1Broadcast ID)=16 Subnets are 192.168.16.0 192.168.16.16 ..... 192.168.16.128 192.168.16.144 (Above this network ID there will be address 192.168.16.143 which is a broadcast ID of Network 192.168.16.128
Shortcut to find 1.First calculate subnets (barrowed 4 bits 2^4=16 subnets) or 256-240 (16) 2. Then do a math (256/16)=16 subnets, if so (144/16)=9 subnets so 144 is a subnet address and 143 is a broadcast address of previous network ID (128) it means (128+16)144
For anyone still confused, I break it down a bit easier: grab 192.168.16.143/28 10001111 is 143 in binary (the last octet is all we're worried about since it's /28). Draw your line at /28, 1000 | 1111. You remember how to get your network/broadcast, first/last? Notice all 1's at the right of the line. That usually means that's your broadcast right? And all 0's is your network. So we can see that this is actually a broadcast.
thx, that's really smart thinking. when all host bits are 1s means broadcast.
Not A: it's possible to configure a private IP address on an interface Not B: /28 is a prefix not a mask, and all routers support them Not C: network addresses are always even numbers (host part all 0's) D: broadcast addresses are always odd numbers (host part all 1's)
D is correct because the next subnet address is 192.168.16.144
subnet address=192.168.16.128 Host address range = 192.168.16.129-192.168.16.142 broadcast address=192.168.16.143
255.255.255.240 -->/28 Block size=256-240=16 Usable IPs. las part of the IP is 143 and there are 144 IPs to 0 to 143. 144/16=9 and hence 192.168.16.143 is a broadcast IP. Explained by Samitha
D is correct Network: 192.168.16.128/28 Broadcast: 192.168.16.143 Usable IPs: 192.168.16.129 - 192.168.16.142
D is definitely correct.
D is correct
1. Find the network address of 192.168.16.143 /28 - 240 = (128 64 32 16) 8 4 2 1 = 128 + 64 +32 +16 -> binary of 255.255.255.240: 1111 0000 (240) -> binary of 192.168.16.143: 1000 1111 (143 = 128 + 8 + 4 +2 +1) -> network address in binary: 1000 0000 (128) -> network address: 192.168.16.128 2. Find the range: - /28: 240 in subnet -> 255 - 240 = 15 hosts - range of hosts: 192.168.16.128 to 192.168.16.143 - first usable: 192.168.16.129 and last usable: 192.168.16.142 -> 192.168.16.143 is a broadcast -> bad mask error ----- Now practice together guys, please solve this 10.10.10.130 /27 is the bad mask 1. find the subnet mask 2. find the network address (find binary of 10.10.10.130 and /27) 3. find range, first usable, and last usable
- 224 = (128+64+32)16 8 4 2= 128+64+32 - binary of 255.255.255.224: 1110 0000(224) - binari of 10.10.10.130: 1000 0010 - network address 128 -255-224 = 31 hosts - range of hosts - 10.10.10.128 to 10.10.10.158 - 10.10.10.129 first usable address -10.10.10.159 broadcast address
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D is correct. If list out the subnet for /28 It will be like 192.168.16.0 192.168.16.16 .. 192.168. 16.128 -------> here the last IP is 192.168. 16.143 is a broadcast 192.168.16.144 192.168.16.160.. Last 192.168. 16.240
Dear moderator Please remove this comment.Thx
According to the mask 255.255.255.240 we take the last octet as reference and subtract to see the subnet increment: 256-240= 16. Then a multiple of 16 close to 143 is searched, in this case it is 144 which would be the following address of network and therefore 143 would be a broadcast address.
D is correct
D is the correct choice Contact me for full questions <a href="/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="deb3bfaaaab7aab7ad9eb1abaab2b1b1b5f0bdb1b3">[email protected]</a>
during the test do we have to do this calculation in our head or will they give us calculator.
Selected D