One thousand concurrent users stream video to their laptops. A 30/70 split between 2.4 GHz and 5 GHz is used.
Based on client count, how many APs (rounded to the nearest whole number) are needed?
One thousand concurrent users stream video to their laptops. A 30/70 split between 2.4 GHz and 5 GHz is used.
Based on client count, how many APs (rounded to the nearest whole number) are needed?
To determine the number of APs needed based on client count, we first calculate the number of users on each frequency band. With a 30/70 split on 1000 users, 700 users connect to the 5 GHz band and 300 users to the 2.4 GHz band. Each AP can handle 25 concurrent users on the 5 GHz band. Dividing 700 users by 25 users per AP, we get 28 APs to manage the 5 GHz connections. Since 28 is the higher number needed to cover the user load, that is the number of APs required.
Correct: B https://documentation.meraki.com/Architectures_and_Best_Practices/Cisco_Meraki_Best_Practice_Design/Best_Practice_Design_-_MR_Wireless/High_Density_Wi-Fi_Deployments
agree with B: The math(s) are 70% of 1000 = 700/25 =28 , and 30% of 1000 = 300/25 = 12. use the greater number out the two calculations, therefore 28
This is not correct. Number of Access Points = Max (Number of Access Points based on throughput, Number of Access Points based on client count).
It's easier for me to remember that each AP can handle 25 concurrent 5GHz connections. I know it's essentially the same thing as the formula, it's just easier for me to remember.
Agree with all, this calculation appears in https://documentation.meraki.com/Architectures_and_Best_Practices/Cisco_Meraki_Best_Practice_Design/Best_Practice_Design_-_MR_Wireless/High_Density_Wi-Fi_Deployments
#APs = (concurrent 5 GHz clients) / 25 = (70% x 1000) / 25 = 28
#APs = (Concurrent 5GHz clients) /25 28 = (70% of 1000) / 25
Correct answer is B - they are asking for client count and not the number of APs based on application. If they noted based on application then it would be aggregate app throughput/device throughput=number of APs. Depending on assumptions that could be C.
What if the question stated 100 users instead of 1000. What would the answer be then?
That would be 3 as the formula is as followed #APs = (Concurrent 5GHz clients) /25 So that means (70% of 100) / 25 = 2.8 and you need to round up so that means 3
Correct: B
2.4 GHz (30% of 1000 = 300 users) Divide by 25 users per AP (best practice) → 300 / 25 = 12 APs 5 GHz (70% of 1000 = 700 users) Divide by 50 users per AP (best practice) → 700 / 50 = 14 APs Total = 12 + 14 = 26 APs
Its c 300 / 25 =12 700 / 40= 27,5 17,5 +12 29,5 nearest is 30
is b only count 5ghz in formule thanks sorry for my error