Refer to the exhibit. PC A is communicating with another device at IP address 10.227.225.255. Through which router does router Y route the traffic?
Refer to the exhibit. PC A is communicating with another device at IP address 10.227.225.255. Through which router does router Y route the traffic?
Based on the given routing table and the destination IP address 10.227.225.255, we must identify the longest prefix match. The relevant subnets in the routing table are: 10.224.0.0/11, 10.128.0.0/9, and 10.0.0.0/8. Among these, the /11 subnet has the longest prefix and covers the range 10.224.0.0 to 10.255.255.255. The destination IP 10.227.225.255 falls within this range. Therefore, the traffic is routed through Router D, which is associated with the next hop 10.224.1.5.
Correct answer is D. Look for the longest match in the routing table.
Makes sense. /11 gives a block of 32. So we are working in the 2nd octet. 224 is the starting network address of that block which would cover up to 256. That would include 227.
The given destination IP address "10.227.225.255" falls and only available in the network "10.0.0.0/8", which goes via Router A with address 10.224.1.2. Let's see the IP ranges of all the given routes: 10.0.0.0/8 = 10.0.0.0 - 10.255.255.255 (Given destination IP "10.227.225.255" falls in this range) 10.128.0.0/9 = 10.128.0.0 - 10.191.255.255 10.224.0.0/11 = 10.224.0.0 - 10.255.255.255 10.224.0.0/15 = 10.224.0.0 - 10.225.255.255 Remaining last 3 subnets are out of picture here: 10.223.0.0/24 10.224.0.0/24 10.226.34.0/24
I assume 10.227.225.255 is part of this range : 10.224.0.0/11 = 10.224.0.0 - 10.255.255.255! so D is correct.
but we need to look at AD right? since both A and D is within range, which A has the lowest AD
I agree, correct answer is "D"
that's right, correct answer is D.
10.224.0.0/8 Obviously is included, but not the longest match. 10.128.0.0/9 Obviously is included, but not the longest match. 10.224.0.0/15 Starts: 10.224.0.0 Ends: 10.225.255.255 10.227.225.255 IS NOT included 10.224.0.0/11 Starts: 10.224.0.0 Ends: 10.255.255.255 10.227.225.255 IS included
Trying to work out why it couldn't be switch C would the /15 not take precedence as it is the longest? and is in the range 10.226.0.1 - 10.227.255.254
Check again for the range, it starts from 10.224.0.1 not from 10.226.0.1.
Can someone please explain in detail how do we go about this question? Thank you all.
ip add 10.227.225.255 take place in the /11 subnet so the next hop is 10.224.1.5 = router D
Thanks mageknight. I understand the process of how it routes but how do you calculate such a big subnet??!!!
you need to understand how to calculate subnets, with a /11 its in the second octet and each subnet is separated by 32. /9 = 128, /10 = 64, /11=32 . therefore 227 would be in that range.
Answer is correct, Static routes have precedence over BGP routes.
and prifix length has precedence over static routes. Answer is D
Comprobado, la respuesta correcta es la D, subnetear mirando las /
The correct answer it's D
10.226.34.0/24 mismatch 10.227 .. correct is 10.224.0.0/15 or no?
it´s D 10.227.225.255/11 Usable IP Range: 10.224.0.1 - 10.255.255.254
You are not considering the type of route, this is a BGP route, Static routes has precedence over BGP routes.
no the logest prefix has precedence first, then lowest AD, then lowest metric.
The destination NWs containing the destination IP address (10.227.225.255) are 10.0.0.0/8, 10.128.0.0/9, and 10.224.0.0/11, and 10.224.0.0/11 is selected as the optimal route by applying Longest Match. Therefore, Router D with its next hop, 10.224.1.5, is the correct answer.
only B is correct answer. 10.128.0.0/9 Usable Host IP Range: 10.128.0.1 - 10.255.255.254 it is contein the offered address
reread the question, the destination ip address is 10.227.225.255, D is correct