DRAG DROP
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Drag and drop the snippets onto the blanks within the code to construct a script that configures BGP according to the topology. Not all options are used, and some options may be used twice.
DRAG DROP
-
Drag and drop the snippets onto the blanks within the code to construct a script that configures BGP according to the topology. Not all options are used, and some options may be used twice.
Given answer is correct. 65001 182.168.1.1 65000 192.168.1.1 https://www.noction.com/blog/bgp-yang-next-generation
Where did you guys get the hint that we're configuring from the client router?
The exam is Enterprise Core so we are the Enterprise/Client not the Service Provider. And the answer is correct.
That is really a piece of creative logic.. after so many questions proving otherwise:)
Okay this makes sense.
the router id is an IP address. ref: https://iosxr-lab-ciscolive.github.io/LTRSPG-2414-cleur2019/wkinstructions/2019-02-01-step-5-playing-iosxr-Yang-Models/ should be 192.168.1.2 192.168.1.1 65000 192.168.1.2
Wouldnt the last one also be .1 since its calling out neighbor again?
yes, it should be .1!
That is what I was saying, it should be .1
You are right, the last then also has to .1
for me it should be as below 192.168.1.2 192.168.1.1 65000 192.168.1.1(
In my opinion: 192.168.1.2 192.168.1.1 65000 192.168.1.2
No, answer is correct ... on client router router bgp 65001 neighbor 192.168.1.1 remote-as 65000 address family ipv4 ... neighbor 192.168.1.1
correct
correct
In BGP configuration, <ios-bgp:id> under the <ios-bgp:bgp> tag refers to the AS number of the local router.