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Question 579

Which QoS forwarding per-hop behavior changes a specific value in a packet header to set the class of service for the packet?

    Correct Answer: D

    Marking is a QoS technique that involves modifying or adding a specific value in a packet header to indicate its class of service. This can be done through fields like the Differentiated Services Code Point (DSCP) in the IP header, which allows routers and switches to apply appropriate QoS policies and forwarding behaviors based on the packet's priority or class.

Discussion
YetiPattyOption: D

forgot to attach my vote lol

YetiPattyOption: D

Answer is correct: Chatgpt: Marking is a QoS technique where a value is modified or added to a specific field in the packet header to indicate the class or priority of the packet. This marking can be used to differentiate and prioritize different types of traffic based on their specific requirements. For example, in IP-based networks, the Differentiated Services Code Point (DSCP) field in the IP header can be modified to set the class of service for a packet. By changing the value of the DSCP field, the packet is marked with a specific priority or class, allowing routers and switches along the network path to apply appropriate QoS policies and forwarding behaviors. Marking is crucial in QoS implementation as it enables network devices to identify and treat packets differently based on their class of service, ensuring that higher-priority traffic, such as voice or real-time applications, receives preferential treatment and appropriate QoS handling.

Bugmenot240411Option: D

Remember, classification identifies, while marking modifies packet headers! --Microsoft Copilot

Brianny93Option: D

IPP Marking DSCP(Differentiated Service Code Point) By having generally agreed upon standard markings for different kinds of traffic. Default Forwarding (DF) - best effort traffic Expedited Forwarding (EF) - Low losslatency/jitter traffic Assured Forward Forwarding (AF) -

SeMo0o0oOption: D

D is correct

Nmk3216Option: D

D is the correct answer.