An existing ceiling raceway system has 115,000 sq mm (177 sq in) of cross-sectional area available for distribution of cable runs. How many can be served by the existing system?
An existing ceiling raceway system has 115,000 sq mm (177 sq in) of cross-sectional area available for distribution of cable runs. How many can be served by the existing system?
The question asks how many can be served by an existing ceiling raceway system that has 115,000 sq mm (177 sq in) of cross-sectional area available for distribution of cable runs. One important factor to consider is if the measurement units are aligned and converted as needed. Without more specific standards or detailed breakdowns of cable area and fill ratio, the answer directly ties the available cross-sectional area to the number of units it can serve. Given that the question presents 115,000 sq mm which converts to 177 sq in, the most reasonable answer is 177, correlating the cross-sectional area directly to the number of units served, aligning with the question's simplicity.
I think this question is based off Figure 18.4, Page 18-16 or 1463. It doesn't give enough information to answer correctly though. 177 would be a guess.
confused
BICSI provides guidelines on the maximum number of cable runs that can be installed in a raceway system based on its cross-sectional area. According to BICSI, the maximum number of cable runs in a raceway system can be calculated as follows: Maximum number of cable runs = Cross-sectional area × (Fill ratio) ÷ Cable area For a typical Category 5e UTP (unshielded twisted pair) cable, the cable area is approximately 32 sq mm (0.05 sq in). Number of cable runs = 115,000 sq mm × (40%) ÷ 32 sq mm = 1,437.5 Now assuming 3 cables per work area (people it can serve) 479 = 1437.5 ÷ 3 Therefore, none of the options (A to E) are correct.
Need help with this one. Can someone explain why?