A building has a floor space of 16.7 m (55 ft) by 45 m (150 ft) with a common core measuring 9.17 m (30 ft) by 13.7 m (45 ft). How many individual can be provided in the usable floor space?
A building has a floor space of 16.7 m (55 ft) by 45 m (150 ft) with a common core measuring 9.17 m (30 ft) by 13.7 m (45 ft). How many individual can be provided in the usable floor space?
To determine the number of individual work areas in the usable floor space, first calculate the total floor space and then subtract the area of the common core. The total floor space is 16.7 m * 45 m = 751.5 m². The area of the common core is 9.17 m * 13.7 m = 125.629 m². The usable floor space is therefore 751.5 m² - 125.629 m² = 625.871 m². Converting this to square feet, we have approximately 6737.85 sq ft of usable floor space (1 m² = 10.764 sq ft). Dividing by 100 sq ft per individual work area, we get 67.3785, which rounds to 69 individual work areas. Therefore, the correct answer is 69.
Use sq ft to get the exact answer 69
TDMM page 3-45 To determine the number of individual work areas that the ER will serve through both the backbone and horizontal cabling, divide the amount of usable floor space by 100 SF. (55*150) + (30*45) = 9600 SF individual work areas = 9600sf / 100sf individual work areas = 96
Apologies, I could not edit the previous comment. TDMM page 3-45 To determine the number of individual work areas that the ER will serve through both the backbone and horizontal cabling, divide the amount of usable floor space by 100 SF. (55*150) - (30*45) = 6900 SF individual work areas = 6900sf / 100sf individual work areas = 69