If an object is placed 1 m (3 ft) away from a light source and the lux level is 3200 lux, what is the lux level at a distance of 8 m (24 ft)?
If an object is placed 1 m (3 ft) away from a light source and the lux level is 3200 lux, what is the lux level at a distance of 8 m (24 ft)?
The inverse square law states that the intensity of light is inversely proportional to the square of the distance from the source. Given this, if the distance is increased by a factor of 8 (from 1 m to 8 m), the lux level would be reduced by a factor of 8 squared (64). Thus, 3200 lux / 64 = 50 lux.
Answer C
Formula: 1m = 3200 lx 2m (1m+1m) -> 3200lx/4 = 800lx 4m (2m+2m) -> 800lx/4 = 200lx 8m (4m+4m) -> 200lx/4 = 50lx Answer C
herefore, the lux level at a distance of 8 m (24 ft) is: C. 50 lux
no estoy de acuerdo con la respuesta que dice ser correcta ya que por formula matematica deberia ser 400,que opinan ustedes
La respuesta correcta es C