Exam ACE-A1.2 All QuestionsBrowse all questions from this exam
Question 48

Which of the following schedule commands will not be accepted by the parser?

    Correct Answer: C

    The command 'show bob's hairy eyeball' is not a valid command and would not be recognized by the parser. Hence, 'schedule test interval 10 max-log-files 10 command show bob's hairy eyeball' will not be accepted by the parser.

Discussion
mahmutaydinOption: D

no answer is D.interval should be greater than 10 B2-DC2-N02-SERVER-3-L-203.23:32:39(config)# schedule test interval 10 max-log-files 10 command show bob's hairy eyeball % For job test, Interval 10 should be greater than the timeout 30 B2-DC2-N02-SERVER-3-L-203.23:32:41(config)# schedule test interval 30 max-log-files 10 command show bob's hairy eyeball % For job test, Interval 30 should be greater than the timeout 30 B2-DC2-N02-SERVER-3-L-203.23:33:58(config)# schedule test interval 31 max-log-files 10 command show bob's hairy eyeball B2-DC2-N02-SERVER-3-L-203.23:34:05(config)#end

network_guruOption: C

A and B would be accepted. The answer is C.