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ACE-A1.2 Exam - Question 48


Which of the following schedule commands will not be accepted by the parser?

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Correct Answer: C

The command 'show bob's hairy eyeball' is not a valid command and would not be recognized by the parser. Hence, 'schedule test interval 10 max-log-files 10 command show bob's hairy eyeball' will not be accepted by the parser.

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mahmutaydinOption: D
Jan 31, 2021

no answer is D.interval should be greater than 10 B2-DC2-N02-SERVER-3-L-203.23:32:39(config)# schedule test interval 10 max-log-files 10 command show bob's hairy eyeball % For job test, Interval 10 should be greater than the timeout 30 B2-DC2-N02-SERVER-3-L-203.23:32:41(config)# schedule test interval 30 max-log-files 10 command show bob's hairy eyeball % For job test, Interval 30 should be greater than the timeout 30 B2-DC2-N02-SERVER-3-L-203.23:33:58(config)# schedule test interval 31 max-log-files 10 command show bob's hairy eyeball B2-DC2-N02-SERVER-3-L-203.23:34:05(config)#end

network_guruOption: C
Jan 26, 2021

A and B would be accepted. The answer is C.