Java EE 6 Java Persistence API Developer Certified Expert

Here you have the best Oracle 1z0-898 practice exam questions

You have 63 total questions to study from
Each page has 5 questions, making a total of 13 pages
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This questions were last updated on October 27, 2025
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Question 1 of 63

Entity lifecycle callback methods may be defined in which three classes? (Choose three)

Embedded classes

Entity classes

Abstract classes

Entity listener classes

Mapped superclasses

Concrete non-entity superclasses

Correct Answer: B, D, E

Question 2 of 63

A developer has created a deep entity class hierarchy with many polymorphic relationships between entitles. Which inheritance strategy, as defined by the inheritanceType enumerated type, will be most performed in this scenario?

Single table-per-class-hierarchy (InheritanceType.SINGLE_TABLE)

Joined-subclass (inheritanceType. JOINED)

Table-per-concrete-class (inheritanceType.TABLE_PER_CLASS)

Polymorphic join table (inheritanceType. POLYMORPHIC_JOIN_TABLE)

Correct Answer: A

Question 3 of 63

A developer is creating an entity which is mapped to a table that has a primary key constraint defined on two character columns and would like to use mapping defaults as much as possible to simplify the code.
Which two mapping options can be chosen? (Choose two.)

Use an @id property that constructs a private field as a concatenation of two columns.

Use a separate class to map those two columns and use an @idclass annotation to denote I primary key field or property in the entity.

Use a separate @Embeddable class to map those two columns and use an @EmbeddedId annotation to denote a single primary key field or property in the entity.

Use a separate @Embeddable class to map those two column and add two fields or properties the entity, each marked as @id, that correspond to the fields or properties in the embeddable class.

Use a separate class to map those two columns. Specify that class using @Idclass annotation on the entity class. Add two fields or properties to the entity,

Correct Answer: C, E

Question 4 of 63

A developer wants to model the grades for a student as a Map<course, integer>. Assume that Student and Course are entitles, and that grades are modeled by integers.
Which of the following two statements are correct? (Choose two)

The developer can model the grades as an element collection in the Student entity.

The developer can model the grades as a oneToMany relationship in the Student entity.

The mapping for the key of the map can be specified by the @MapKeycolumn annotation.

The mapping for the value of the map can be specified by the @Column annotation.

Correct Answer: A, D

A: JPA 2.0 defines an ElementCollection mapping. It is meant to handle several non-standard relationship mappings. An ElementCollection can be used to define a one-to-many relationship to an Embeddable object, or a Basic value (such as a collection of Strings). An ElementCollection can also be used in combination with a Map to define relationships where the key can be any type of object, and the value is an Embeddable object or a Basic value.
D:
Example of an ElementCollection relationship database:
Exam 1z0-898: Question 4 - Image 1

Example of an ElementCollection relationship annotations
@Entity
public class Employee {
@Id
@Column(name="EMP_ID")
private long id;
...
@ElementCollection
@CollectionTable(
name="PHONE",
joinColumns=@JoinColumn(name="OWNER_ID")
)
private List<Phone> phones;
...
}
@Embeddable
public class Phone {
private String type;
private String areaCode;
@Column(name="P_NUMBER")
private String number;
...
}
Reference: Java Persistence/ElementCollection AD

Question 5 of 63

Consider a persistence application with the following orm.xml:
Exam 1z0-898: Question 5 - Image 1

What will be the effect of the above orm.xml?

The access type for only those entities that have not explicitly specified @Access will be defaulted to field.

The access type for all entities in the persistence unit will be changed to FIELD.

The access type for all entities specified in this orm.xml will be changed to FIELD.

The access type for only those entities defined in this orm.xml for which access is not specified will be defaulted to FIELD.

Correct Answer: D