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Cisco 200-301

Cisco Certified Network Associate (CCNA)

Verified practice questions with detailed answers, clear explanations, and community discussion.

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Question 1 of 1395

Exam 200-301: Question 1 - Image 1

Refer to the exhibit. Which type of route does R1 use to reach host 10.10.13.10/32?

Answer choices
Show answer

Correct answer: B

R1 uses a network route to reach host 10.10.13.10/32. The routing table contains a route to the network 10.10.13.0/25, which means it can reach any host within the 10.10.13.0 network, including 10.10.13.10. The subnet mask /25 indicates that this route is intended for the entire subnet, not just a single host, confirming that it is a network route.

Community votes

58 votes

BSuggested

86%

C

9%

D

3%

A

2%

Question 2 of 1395

Exam 200-301: Question 2 - Image 1

Refer to the exhibit. Which prefix does Router1 use for traffic to Host A?

Answer choices
Show answer

Correct answer: D

Router1 will use the prefix 10.10.13.208/29 for traffic to Host A (10.10.13.214). This is because the /29 subnet mask provides the most specific match for this IP address. Specifically, the 10.10.13.208/29 prefix includes IP addresses from 10.10.13.208 to 10.10.13.215, which encompasses the IP address of Host A. In routing, the most specific match (longest prefix) is always chosen to ensure efficient routing. Therefore, 10.10.13.208/29 is the correct prefix.

Community votes

33 votes

DSuggested

97%

A

3%

Question 3 of 1395

DRAG DROP -

Drag and drop the descriptions of file-transfer protocols from the left onto the correct protocols on the right.

Select and Place:

Exam 200-301: Question 3 - Image 1
Show answer

Suggested answer

Exam 200-301: Question 3 - Image 2

Question 4 of 1395

A frame that enters a switch fails the Frame Check Sequence. Which two interface counters are incremented? (Choose two.)

Answer choices
Show answer

Correct answers: A, D

When a frame enters a switch and fails the Frame Check Sequence (FCS), it indicates that the frame has encountered an error during transmission. This type of error is detected through the Cyclic Redundancy Check (CRC) process. As a result, two specific interface counters are incremented. The 'input errors' counter is incremented because it tallies all incoming errors, including CRC errors, giants, runts, and other types of errors. Simultaneously, the 'CRC' counter is incremented since it specifically logs the number of frames that failed the CRC check. These increments help network administrators identify and troubleshoot issues related to data transmission errors.

Community votes

20 votes

ADSuggested

90%

D

10%

Question 5 of 1395

DRAG DROP -

Drag and drop the IPv4 network subnets from the left onto the correct usable host ranges on the right.

Select and Place:

Exam 200-301: Question 5 - Image 1
Show answer

Suggested answer

This subnet question requires us to grasp how to subnet very well. To quickly find out the subnet range, we have to find out the increment and the network address of each subnet. Let's take an example with the subnet 172.28.228.144/18:
From the /18 (= 1100 0000 in the 3rd octet), we find out the increment is 64. Therefore the network address of this subnet must be the greatest multiple of the increment but not greater than the value in the 3rd octet (228). We can find out the 3rd octet of the network address is 192 (because 192 = 64 * 3 and 192 < 228) -
> The network address is 172.28.192.0. So the first usable host should be 172.28.192.1 and it matches with the 5th answer on the right. In this case we don't need to calculate the broadcast address because we found the correct answer.
Let's take another example with subnet 172.28.228.144/23 -> The increment is 2 (as /23 = 1111 1110 in 3rd octet) -> The 3rd octet of the network address is 228
(because 228 is the multiply of 2 and equal to the 3rd octet) -> The network address is 172.28.228.0 -> The first usable host is 172.28.228.1. It is not necessary but if we want to find out the broadcast address of this subnet, we can find out the next network address, which is 172.28.(228 + the increment number).0 or
172.28.230.0 then reduce 1 bit -> 172.28.229.255 is the broadcast address of our subnet. Therefore the last usable host is 172.28.229.254. Exam 200-301: Question 5 - Image 2

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Honestly, I had already gone through the official documentation quite thoroughly, but still didn't feel fully confident going in. This helped things finally click for me. I realized I knew the material, but just hadn't connected all the pieces yet.
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I don't usually leave reviews, but this one felt worth sharing. The questions were quite close to what actually appeared on the exam, more than I expected. I spent about a week going through the material before my test, and it helped me feel more prepared.
Remi Nuyts
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Archie Hopkins
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I had a smooth experience from start to finish. Access was available right away, no technical issues, which made it easy to get started. The content felt relevant and aligned well with what I was looking for.
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A very quick response was received via email when a link issue occurred. The study materials provided were high quality and extremely helpful. I was able to complete the test successfully. Many thanks for the excellent support.

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