If the MAC address of an interface is 0EE0-FFFE-0FEC, the corresponding EUI-64 address is ( ).
If the MAC address of an interface is 0EE0-FFFE-0FEC, the corresponding EUI-64 address is ( ).
The EUI-64 address is derived from the MAC address by splitting the MAC address into two halves and inserting 'FFFE' in between. Additionally, the 7th bit of the first byte is flipped. In this case, the MAC address is 0EE0-FFFE-0FEC. Splitting it into two halves gives '0EE0' and '0FEC'. Inserting 'FFFE' in the middle results in '0EE0-FFFF-FEFE-0FEC'. To flip the 7th bit of the first byte (which is E0 in hexadecimal, or 11100000 in binary), the result is C0 (11000000 in binary). Therefore, the final EUI-64 address is 0CE0-FFFF-FEFE-0FEC.
A is the correct answer E=14 and E=1110 and 7bit =1 the inverse of 7 bit=0 hence 12=C so the correct=0CE0:FFFF:FEFE:0FEC
RPTA CORRECTA: A 0CE0-FFFF-FEFE-0FEC
1:> Split the MAC in the Middle 2:> Insert FF:FE in the middle 3:> Convert the first 8 bits into binary 4:> Flip the 7th bit 5:> Convert the first 8 bits to Hex
A is correct
A 0CE0-FFFF-FEFE-0FEC
It's A.
B is correct guys
B is correct = 0EE0-FFFE-0FEC we split the mac in two 24 bits parts and insert FFFE as : 0EE0-FF FFFE FE-0FEC