DRAG DROP -
Refer to the exhibit. The IP address configurations must be completed on the DC-1 and HQ-1 routers based on these requirements:
✑ DC-1 Gi1/0 must be the last usable address on a /30
✑ DC-1 Gi1/1 must be the first usable address on a /29
✑ DC-1 Gi1/2 must be the last usable address on a /28
✑ HQ-1 Gi1/3 must be the last usable address on a /29
Drag and drop the commands from the left onto the destination interfaces on the right. Not all commands are used.
Select and Place:
Broadcast: odd Network: even 1st usable: odd last usable: even
This is the best answer here. This way you can resolve the question very fast without doing all the math, and save time.
Please, what's the significance of this coded info
Check whether the last digit in the IP address is odd or even
Really appreciate!!! It's really a magic method.
If this question appears on the exam, I will likely skip it because of the time required to do the math. If possible, I would save it to the end to attempt only if I have extra time.
It's something I'm trying to understand: you CAN skip it and review it in a second time? Someone know the answer?
I think once you skip and click next you can't go back
I know someone who recently took the CCNA Exam and told me you can't go back to a previous question or flag it for review later unlike CompTIA Exams.
given answers are correct
/28 SM should 255.255.255.240 Last usable address of the network 192.168.3.0/28 is 192.168.3.14 (192.168.3.0-192.168.3.15) /29 SM should be 255.255.255.248 The first usable address of the network 192.168.4.8/29 is 192.168.4.9(192.168.4.8-192.168.4.15) The last usable address of the network 192.168.3.8/29 is 192.168.3.14(192.168.3.8-192.168.3.15) /30 SM should be 255.255.255.252 The last octet of the network ID should be a multiple of 4 since every sub-network will have 4 IPs Network with network ID 209.165.202.128 (209.165.202.128-209.265.202.131) Last usable address 209.165.202.131
Correction: For Network with network ID 209.165.202.128 (209.165.202.128-209.265.202.131) The Last usable address should be 209.165.202.130.
209.165.202.131 is the Broadcast address.
Yes, you're right, thank you!
G1/2 and G1/3 have the same IP address. Is that okay???
IMHO someone should correct the 1st Questinon from "DC-1 Gi1/0 must be the last usable address on a /30" to this Q & A "DC-1 Gi1/0 must be the first usable address on a /30" then you can choose IP-Address 209.165.202.131 255.255.255.252, otherwise it simply doesn't make sense to me...
Given answer is correc
Gi1/1 & Gi1/3 are on the same subnet 255.255.255.248
Answer given is correct. Just take time and do it on paper
I think the question should have read => HQ-1 Gi1/1 must be the last usable address on a /29 instead of HQ-1 Gi1/3. There are options from the selections to make the two switches non-overlapping.
I meant to say: I think the question should have read => HQ-1 Gi1/1 must be the last usable address on a /29 instead of HQ-1 Gi1/3. There are "NO" options from the selections to make the two switches non-overlapping.
Sorry, for the confusion,... just figured out, that I had a little miscalculation with the /30 .252 Network Address is 209.165.202.128 so 130 will be fine. But I guess that's intended to be...
Key word is "last usable address/ first usable addrss", check all possible subnet addresses then find if that is the last or first.
can someone help to explain how the answers were get? I'm confused.
/30 means the subnet will be .252 hosts will go in groups of 4 /29 means subnet will be .248 hosts will go in groups of 8 /28 means subnet will be .240 hosts will go in groups of 16 Now if you need to see how to get first host, last host and broadcast addresses, I recommend you study that separately. To practice those exercises, go here: https://www.subnetting.net/Subnetting.aspx?mode=practice