Refer to the exhibit. Which two commands are needed to allow for full reachability between AS 1000 and AS 2000? (Choose two.)
Refer to the exhibit. Which two commands are needed to allow for full reachability between AS 1000 and AS 2000? (Choose two.)
To allow for full reachability between AS 1000 and AS 2000, R2 needs to remove the incorrect advertisement of the 10.0.0.0/24 network, as it actually belongs to AS 1000 and should not be announced by R2. The command 'no network 10.0.0.0 255.255.255.0' on R2 accomplishes this. Additionally, R2 should advertise its own network, which is 192.168.0.0/16, to make it known to AS 1000. The command 'network 192.168.0.0 mask 255.255.0.0' on R2 accomplishes this.
A & C are correct. Need to negate the 10.0.0.0 /24 network on R2 and then add the 192.168.0.0 /16 network on R2. Hence, A & C, although I think to be exact the answer on A should be "no network 10.0.0.0 mask 255.255.255.0" vs. the "no network 10.0.0.0 255.255.255.0".
Basically R2 need to advertise the network 182.168…. Not 10.0….
The answers are correct but I think there is a typo in A.
What's the typo? If you are referring to being in the proper configuration mode, then C also has a typo. Otherwise A has correct syntax: the network being removed is a /24 or 255.255.255.0 subnet mask.
if you're using the "no" command, then you'd have to undo the command written in the proper way, which would be "network 10.0.0.0 MASK 255.255.255.0", correct? Answer A is missing the "mask" part in the command, which I agree with iGlitch, is probably a typo, but still would be the best choice for one of the two correct answers.
A & C are correct
R1 do not need anything to be changed and all correct, so D & E not the answer straight. between A,B,C , B is the network interface running on its onw, its not the neighbor, so B removed as well left over A & C is the answer
correct
given answer is correct
A C seems to me
A & D are the correct answer.
the given answer is correct
You need what D is removing, so that R1 advertises the 10.0.0.0/24 network
The given answer is correct